
Example 1:
int a;
float b;
a + b
Results in:
1. Convert a to a float representation
2. Add the 2 float values

Example 2:
short a;
int b;
a + b
Results in:
1. Convert a to an int (64 bits) representation
2. Add the 2 int values

byte (1 byte integer (whole number) representation for values between 127..128) short (2 byte integer (whole number) representation for values between 32767..32768) int (4 byte integer (whole number) representation) 

The value 3 (three dots) is represented as follows: As byte type using 1 byte (8 bits): 00000011 As short type using 2 bytes (16 bits): 0000000000000011 As int type using 4 bytes (32 bits): 00000000000000000000000000000011 
The value 3 is represented as follows: As byte type using 1 byte (8 bits): 11111101 As short type using 2 bytes (16 bits): 1111111111111101 As int type using 4 bytes (32 bits): 11111111111111111111111111111101 

Example:
The representation of the value 3 in 8 bits is: 00000011 When we convert this 8 bit representaion into a 16 bit representation, the result is: 0000000000000011 Because: The binary number represents the (same) value 3 !!! 




is called:


EXT.W Dn Converts an 8bits 2's complement representation in reg Dn to a 16 bits 2's complement representation (in reg Dn) In other words: convert a byte typed value in reg Dn into a short typed value EXT.L Dn Converts a 16bits 2's complement representation in reg Dn to a 32 bits 2's complement representation (in reg Dn) In other words: convert a short typed value in reg Dn into a int typed value 
Examples:
(1) Starting with: +++++ D0 =  10101010  01010101  10101010  11111110  +++++ ^^^^^^^^ This byte represents the byte typed value "2" After "EXT.W D0", we will have: +++++ D0 =  10101010  01010101  11111111  11111110  +++++ ^^^^^^^^^^^^^^^^^^^ This WORD represents the short typed (same) value "2" ! (2) Starting with: +++++ D0 =  10101010  01010101  11111111  11111100  +++++ ^^^^^^^^^^^^^^^^^^^ This WORD represents the short typed value "2" After "EXT.L D0", we will have: +++++ D0 =  11111111  11111111  11111111  11111110  +++++ ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ This LONG WORD (= 32 bits) represents the int typed value "2" ! 
How to run the program:



The value 3 (three dots) is represented as follows: Using 4 bytes (32 bits): 00000000000000000000000000000011 Using 2 bytes (16 bits): 0000000000000011 (= truncate upper 16 bits) Using 1 byte (8 bits): 00000011 (= truncate upper 24 bits) 
The value 3 is represented as follows: Using 4 bytes (32 bits): 11111111111111111111111111111101 Using 2 bytes (16 bits): 1111111111111101 Using 1 byte (8 bits): 11111101 
